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5x^2+6x-8=-7
We move all terms to the left:
5x^2+6x-8-(-7)=0
We add all the numbers together, and all the variables
5x^2+6x-1=0
a = 5; b = 6; c = -1;
Δ = b2-4ac
Δ = 62-4·5·(-1)
Δ = 56
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{56}=\sqrt{4*14}=\sqrt{4}*\sqrt{14}=2\sqrt{14}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(6)-2\sqrt{14}}{2*5}=\frac{-6-2\sqrt{14}}{10} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(6)+2\sqrt{14}}{2*5}=\frac{-6+2\sqrt{14}}{10} $
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